AgCl dissolves in ammonia solution giving

Options

A. `Ag^(+), NH_(4)^(+)` and `Cl^(-)`
B. `Ag(NH_(3))^(+)` and `Cl^(-)`
C. `Ag_(2)(NH_(3))^(2+)` and `Cl^(-)`
D. `Ag(NH_(3))_(2)^(+)` and `Cl^(-)`

Answer

To solve the question "AgCl dissolves in ammonia solution giving," we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactant in this case is silver chloride (AgCl) and ammonia (NH₃) solution.

2. **Understand the Reaction**:
- When AgCl is added to an ammonia solution, it reacts to form a complex ion.

3. **Write the Reaction**:
- The reaction can be represented as:
\[ \text{AgCl (s)} + 2 \text{NH}_3 (aq) \rightarrow [\text{Ag(NH}_3\text{)}_2]^+ + \text{Cl}^- \]
- Here, AgCl dissolves in the presence of ammonia to form the complex ion \([\text{Ag(NH}_3\text{)}_2]^+\) and a chloride ion (\(\text{Cl}^-\)).

4. **Identify the Products**:
- The products of the reaction are the complex ion \([\text{Ag(NH}_3\text{)}_2]^+\) and the chloride ion \(\text{Cl}^-\).

5. **Conclusion**:
- Thus, the dissolution of AgCl in ammonia results in the formation of the complex ion \([\text{Ag(NH}_3\text{)}_2]^+\) and \(\text{Cl}^-\).

### Final Answer:
AgCl dissolves in ammonia solution giving \([\text{Ag(NH}_3\text{)}_2]^+\) and \(\text{Cl}^-\).

---