A solution of a salt in concentrated sulphuric acid `H_(2)SO_(4)` acid produced a deep blue colour with starch iodide solution.The salt may be

Options

A. chloride
B. carbonate
C. acetate
D. bromide

Explanation

To solve the problem of identifying the salt that produces a deep blue color with starch iodide solution when reacted with concentrated sulfuric acid (H₂SO₄), we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Reaction**: We need to identify a salt that, when dissolved in concentrated sulfuric acid, will produce a product that reacts with starch iodide to give a deep blue color.

2. **Identify Possible Salts**: The question implies that there are several salts to consider. Common salts that might be tested include chlorides, bromides, and iodides.

3. **Reactions with Concentrated H₂SO₄**:
- When a bromide salt (e.g., potassium bromide, KBr) is treated with concentrated sulfuric acid, it reacts to produce hydrogen bromide (HBr) and bisulfate ion (HSO₄⁻).
- The reaction can be represented as:
\[ \text{KBr} + \text{H}_2\text{SO}_4 \rightarrow \text{HBr} + \text{KHSO}_4 \]

4. **Further Reaction of HBr**: The hydrogen bromide can further react with sulfuric acid:
\[ \text{HBr} + \text{H}_2\text{SO}_4 \rightarrow \text{Br}_2 + \text{SO}_2 + \text{H}_2\text{O} \]
Here, bromine (Br₂) is produced.

5. **Reaction with Starch Iodide**: The produced bromine (Br₂) can then react with starch iodide. The starch iodide complex forms a deep blue color due to the presence of iodine (I₂) in the solution:
\[ \text{Br}_2 + \text{Starch-Iodide} \rightarrow \text{Deep Blue Complex} \]

6. **Conclusion**: Since the deep blue color is observed, we can conclude that the salt must be a bromide salt, as it is the only one that produces bromine when reacted with concentrated sulfuric acid.

### Final Answer:
The salt may be a bromide salt.

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