Home
Class 12
CHEMISTRY
There are four test tubes containing dil...

There are four test tubes containing dilute `HCl,BaCl_(2),CdCl_(2)` and `KNO_(3)` soluitons.Which of the following reagents with help in the identification of `BaCl_(2)`?

A

`NaOH`

B

`K_(2)CrO_(4)`

C

`AgNO_(3)`

D

both (B) and ( C)

Text Solution

AI Generated Solution

The correct Answer is:
To identify barium chloride (BaCl₂) among the given solutions (dilute HCl, BaCl₂, CdCl₂, and KNO₃), we can use a specific reagent that reacts with barium ions to form a distinct precipitate. Here is a step-by-step solution: ### Step-by-Step Solution: 1. **Identify the Reagents**: The reagents provided are NaOH, K₂CrO₄, HCl, and AgNO₃. We need to determine which of these can help identify BaCl₂. 2. **Test with NaOH**: - When NaOH is added to BaCl₂, it reacts to form barium hydroxide (Ba(OH)₂) and sodium chloride (NaCl). - Reaction: \[ \text{BaCl}_2 + 2 \text{NaOH} \rightarrow \text{Ba(OH)}_2 + 2 \text{NaCl} \] - Both Ba(OH)₂ and NaCl are soluble in water, so no precipitate forms. Thus, NaOH cannot be used to identify BaCl₂. 3. **Test with K₂CrO₄**: - When K₂CrO₄ is added to BaCl₂, it reacts to form barium chromate (BaCrO₄), which is a yellow precipitate. - Reaction: \[ \text{Ba}^{2+} + \text{CrO}_4^{2-} \rightarrow \text{BaCrO}_4 \, (\text{yellow precipitate}) \] - The formation of a yellow precipitate indicates the presence of barium ions, thus K₂CrO₄ can be used to identify BaCl₂. 4. **Test with HCl**: - Adding HCl to BaCl₂ does not produce any precipitate since both BaCl₂ and HCl are soluble in water. Therefore, HCl cannot be used to identify BaCl₂. 5. **Test with AgNO₃**: - When AgNO₃ is added to BaCl₂, it forms silver chloride (AgCl), which is a white precipitate. - Reaction: \[ \text{BaCl}_2 + 2 \text{AgNO}_3 \rightarrow 2 \text{AgCl} \, (\text{white precipitate}) + \text{Ba(NO}_3)_2 \] - However, AgCl can also form with other chloride solutions, making it less specific for identifying BaCl₂. 6. **Conclusion**: The best reagent to identify BaCl₂ is K₂CrO₄, as it produces a distinct yellow precipitate of barium chromate. ### Final Answer: The reagent that will help in the identification of BaCl₂ is **K₂CrO₄**. ---
To identify barium chloride (BaCl₂) among the given solutions (dilute HCl, BaCl₂, CdCl₂, and KNO₃), we can use a specific reagent that reacts with barium ions to form a distinct precipitate. Here is a step-by-step solution: ### Step-by-Step Solution: 1. **Identify the Reagents**: The reagents provided are NaOH, K₂CrO₄, HCl, and AgNO₃. We need to determine which of these can help identify BaCl₂. 2. **Test with NaOH**: - When NaOH is added to BaCl₂, it reacts to form barium hydroxide (Ba(OH)₂) and sodium chloride (NaCl). ...
Promotional Banner

Similar Questions

Explore conceptually related problems

There are four test tubes containing dilute HCl, BaCl_(2), HgCl_(2) " and" KNO_(3) solutions. Which of the following reagents will help in the identification of BaCl_(2) ?

Which of the following complex will give white ppt. with BaCl_(2) solution ?

Blue litmus solution is added to two test tubes A and B containing dilute HCl and NaOH solution respectively. In which test tube a color change will be observed? State the colour change and give its reason.

Among the following coordination compounds, the one giving a white ppt. with BaCl_2 is

(i) A white solid mixture of two salts containing a common cations in insoluble in water. It dissolves in dilute HCl producing some gases (with effervescence) that turn an acidified dichromate solution gren. After the gases are passed through the acidified dichromate solution, the emerging gas turns baryta water milky. (ii) On treatment with dilute HNO_(3) , the white solid gives a solution which does not directly give a precipitate with a BaCl_(2) solution but gives a white precipitate when warmed with H_(2)O_(2) and then treated with a BaCl_(2) solution. (iii) The solution of the mixture in dilute HCl, when treated with NH_(4)Cl,NH_(4)OH and an Na_(2)HPO_(4) solution, gives a white precipitate. Q. The white precipitate obtained in (ii) indicates the presence of a:

(i) A white solid mixture of two salts containing a common cations in insoluble in water. It dissolves in dilute HCl producing some gases (with effervescence) that turn an acidified dichromate solution gren. After the gases are passed through the acidified dichromate solution, the emerging gas turns baryta water milky. (ii) On treatment with dilute HNO_(3) , the white solid gives a solution which does not directly give a precipitate with a BaCl_(2) solution but gives a white precipitate when warmed with H_(2)O_(2) and then treated with a BaCl_(2) solution. (iii) The solution of the mixture in dilute HCl, when treated with NH_(4)Cl,NH_(4)OH and an Na_(2)HPO_(4) solution, gives a white precipitate. Q. The white precipitate obtained in (iii) consists of:

If equal volumes of BaCl_(2) and NaF solutions are mixed, which of these combination will not give a precipitate? (K_(sp) of BaF_(2) =1.7 xx 10^(-7)) .

You are provided with two containers made up of copper and aluminium. You are also provided with solutions of dilute HCl, dilute HNO_(3),ZnCl_(2) and H_(2)O . In which of the containers these solutions can be kept?

The osmotic pressure of equimolar solutions of BaCl_(2) , NaCl ,and glucose follow the order

The osmotic pressures of equimolar solutions of urea , BaCl_(2) and AlCl_(3) will be in the order :