Ammonia/ammonium ion gives yellow precipitate with:

Options

A. `H_(2)PtCl_(6)`
B. `HgCl_(2)`
C. `Na_(3)[Co(NO_(2))_(6)]`
D. (A) and ( C) both

Explanation

To determine which compounds give a yellow precipitate when reacted with ammonia or ammonium ions, we can analyze the reactions step by step.

### Step-by-Step Solution:

1. **Identify the Compounds**:
We need to identify the compounds that are known to react with ammonia (NH3) or ammonium ions (NH4+). In this case, we are considering:
- H2PtCl6 (Hexachloroplatinic acid)
- Co(NO2)3 (Cobalt(III) nitrate)

2. **Reaction with H2PtCl6**:
- When ammonium ions (NH4+) react with H2PtCl6, they form a complex:
\[ 2 NH4^+ + PtCl6^{2-} \rightarrow (NH4)_2PtCl6 \]
- The product, \((NH4)_2PtCl6\), is a yellow-colored precipitate.

3. **Reaction with Co(NO2)3**:
- Similarly, when ammonium ions react with Co(NO2)3, the reaction is:
\[ 3 NH4^+ + Co(NO2)3 \rightarrow (NH4)_3Co(NO2)3 \]
- The product, \((NH4)_3Co(NO2)3\), is also a yellow-colored precipitate.

4. **Conclusion**:
- Both H2PtCl6 and Co(NO2)3 react with ammonium ions to form yellow precipitates. Therefore, the compounds that give a yellow precipitate with ammonia/ammonium ion are H2PtCl6 and Co(NO2)3.

### Final Answer:
The compounds that give a yellow precipitate with ammonia/ammonium ion are:
- H2PtCl6
- Co(NO2)3