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To increase significantly the concentrat...

To increase significantly the concentration of free `Zn^(2+)` ion is a solution of the complex ion `[Zn(NH_(3))_(4)]^(2+)`
`Zn^(2+) (aq)+4NH_(3) (aq) hArr [Zn(NH_(3))_(4)]^(2+) (aq)`
Add to the solution some:

A

`H_(2)O`

B

`HCl(aq)`

C

`NH_(3)(aq)`

D

`NH_(4)Cl(aq)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of how to increase the concentration of free \( \text{Zn}^{2+} \) ions in a solution of the complex ion \( [\text{Zn(NH}_3)_4]^{2+} \), we need to analyze the equilibrium reaction given: \[ \text{Zn}^{2+} (aq) + 4 \text{NH}_3 (aq) \rightleftharpoons [\text{Zn(NH}_3)_4]^{2+} (aq) \] ### Step-by-Step Solution: 1. **Understanding the Equilibrium**: The reaction shows that \( \text{Zn}^{2+} \) ions combine with ammonia (\( \text{NH}_3 \)) to form the complex ion \( [\text{Zn(NH}_3)_4]^{2+} \). To increase the concentration of free \( \text{Zn}^{2+} \) ions, we need to shift the equilibrium to the left. 2. **Le Chatelier's Principle**: According to Le Chatelier's Principle, if we change the conditions of a system at equilibrium, the system will adjust to counteract that change. In this case, if we decrease the concentration of \( \text{NH}_3 \), the equilibrium will shift to the left to produce more \( \text{NH}_3 \) and, consequently, more \( \text{Zn}^{2+} \) ions. 3. **Adding HCl**: When we add hydrochloric acid (HCl) to the solution, it reacts with ammonia (\( \text{NH}_3 \)) to form ammonium chloride (\( \text{NH}_4\text{Cl} \)). This reaction reduces the concentration of \( \text{NH}_3 \) in the solution. \[ \text{NH}_3 (aq) + \text{HCl} (aq) \rightarrow \text{NH}_4\text{Cl} (aq) \] 4. **Effect on the Equilibrium**: As the concentration of \( \text{NH}_3 \) decreases due to the formation of \( \text{NH}_4\text{Cl} \), the equilibrium will shift to the left to compensate for the loss of \( \text{NH}_3 \). This shift will result in the decomposition of the complex ion \( [\text{Zn(NH}_3)_4]^{2+} \), thereby increasing the concentration of free \( \text{Zn}^{2+} \) ions in the solution. 5. **Conclusion**: Therefore, the correct choice to increase the concentration of free \( \text{Zn}^{2+} \) ions in the solution is to add **HCl**. ### Final Answer: Add **HCl** to the solution.
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