Home
Class 12
CHEMISTRY
An aqueous solution of colourless metal ...

An aqueous solution of colourless metal sulphate `M`, gives a white precipitate with `NH_(4)OH`.This was soluble in excess of `NH_(4)OH`. On passing `H_(2)S` through this solution a white precipitate is formed.The metal `M` in the salt is:

A

`Ca`

B

`Ba`

C

`Al`

D

`Zn`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will analyze the information given in the question and apply our knowledge of qualitative analysis. ### Step 1: Identify the Metal Sulfate The problem states that we have a colorless metal sulfate `M` that forms a white precipitate with `NH4OH` (ammonium hydroxide). This indicates that the metal ion `M` likely forms a hydroxide that is insoluble in water. **Hint:** Look for metal ions that form insoluble hydroxides. ### Step 2: Analyze the Precipitate with NH4OH When `NH4OH` is added to the solution, a white precipitate is formed. The fact that this precipitate is soluble in excess `NH4OH` suggests that the metal ion is likely zinc (Zn²⁺), as zinc hydroxide (Zn(OH)₂) is known to be amphoteric and dissolves in excess `NH4OH` to form a soluble complex. **Hint:** Remember that amphoteric hydroxides can dissolve in excess base. ### Step 3: Reaction with H2S Next, the problem states that when `H2S` (hydrogen sulfide) is passed through the solution, a white precipitate is formed. Zinc sulfide (ZnS) is a white precipitate that forms when `H2S` is introduced to a solution containing zinc ions. **Hint:** Consider the sulfides that form from metal ions in solution. ### Step 4: Conclusion Based on the observations: 1. The formation of a white precipitate with `NH4OH` that is soluble in excess indicates the presence of zinc. 2. The formation of a white precipitate with `H2S` confirms the presence of zinc, as it forms zinc sulfide. Thus, the metal `M` in the salt is **Zinc (Zn)**. ### Final Answer: The metal `M` in the salt is **Zinc (Zn)**.
To solve the problem step by step, we will analyze the information given in the question and apply our knowledge of qualitative analysis. ### Step 1: Identify the Metal Sulfate The problem states that we have a colorless metal sulfate `M` that forms a white precipitate with `NH4OH` (ammonium hydroxide). This indicates that the metal ion `M` likely forms a hydroxide that is insoluble in water. **Hint:** Look for metal ions that form insoluble hydroxides. ### Step 2: Analyze the Precipitate with NH4OH ...
Doubtnut Promotions Banner Mobile Dark
|

Similar Questions

Explore conceptually related problems

An aqueous solution of a substance, on treatment with dilute HCl, gives a white precipitate soluble in hot water. When H_(2)S is passed through the hot acidic solution, a black precipitate is formed. The substance is:

Name : a metallic hydroxide soluble in excess of NH_( 4)OH .

Knowledge Check

  • An inorganic compound (X) shows the following reactions : (a) It is white solid, exists as dimer and fumes in moist air. (b) It sublimes at 180^@ C and forms monomer on heating to 400^@ C . ( c) Its aqueous solution turns blue litmus red and gives a white precipitate with AgNO_(3) solution which is soluble in excess of NH_(4) OH . (d) Addition of NaOH to the solution of (A) gives a white gelatinous precipitate which is, however, soluble on excess of NaOH . Identify the compound (A) .

    A
    `AI(OH)_(3)`
    B
    `AI_(2)CI_(6)`
    C
    `AI_(2)O_(3)`
    D
    `AI_(2)(SO_(4))_(3)`

    • Similar Questions

    Explore conceptually related problems

    When H_(2)S gas a passed through an ammonical salt solution X, a slightly white precipitate is formed. The X can be:

    A white amorphous powder (A) when heated gives a colourless gas (B), which turns lime water milky and the residue (C) which is yellow when hot but white when cold. The residue (C) dissolves in dilute HCl and the resulting solution gives a white precipitate on addition of potassium ferrocyanide solution. (A) dissolves in dilute HCl with the evolution of a gas which is identical in all respects with (B). The solution of (A) as obtained above gives a white precipitate (D) on addition of excess of NH_(4)OH and on passing H_(2)S . Another portion of this solution gives initially a white precipitate (E) on addition of NaOH which dissolves in excess of it. Compounds (A) to (E) are identified as:

    H_(2)S gas on passing through an alkline solution , forms a white precipitate .The solution contains ions of

    To a solution of a substance gradual addition of ammonium hydroxide result in a black precipitate which does not dissolve in excess of NH_(4)OH however when HCI is added to the original solution a white precipitate is formed .The solution containe

    Which of the following precipitate is soluble in excess of NH_(3) solution?

    An aqueous solution of salt gives salt precipitate with AgNO_(3) solution as well as with dilute H_(2)SO_(4) . It may be

    When of the following precipitate is soluble in excess of NH_(3) solution?

    Home
    Profile