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An aqueous solution of colourless metal ...

An aqueous solution of colourless metal sulphate `M`, gives a white precipitate with `NH_(4)OH`.This was soluble in excess of `NH_(4)OH`. On passing `H_(2)S` through this solution a white precipitate is formed.The metal `M` in the salt is:

A

`Ca`

B

`Ba`

C

`Al`

D

`Zn`

Text Solution

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The correct Answer is:
To solve the problem step by step, we will analyze the information given in the question and apply our knowledge of qualitative analysis. ### Step 1: Identify the Metal Sulfate The problem states that we have a colorless metal sulfate `M` that forms a white precipitate with `NH4OH` (ammonium hydroxide). This indicates that the metal ion `M` likely forms a hydroxide that is insoluble in water. **Hint:** Look for metal ions that form insoluble hydroxides. ### Step 2: Analyze the Precipitate with NH4OH When `NH4OH` is added to the solution, a white precipitate is formed. The fact that this precipitate is soluble in excess `NH4OH` suggests that the metal ion is likely zinc (Zn²⁺), as zinc hydroxide (Zn(OH)₂) is known to be amphoteric and dissolves in excess `NH4OH` to form a soluble complex. **Hint:** Remember that amphoteric hydroxides can dissolve in excess base. ### Step 3: Reaction with H2S Next, the problem states that when `H2S` (hydrogen sulfide) is passed through the solution, a white precipitate is formed. Zinc sulfide (ZnS) is a white precipitate that forms when `H2S` is introduced to a solution containing zinc ions. **Hint:** Consider the sulfides that form from metal ions in solution. ### Step 4: Conclusion Based on the observations: 1. The formation of a white precipitate with `NH4OH` that is soluble in excess indicates the presence of zinc. 2. The formation of a white precipitate with `H2S` confirms the presence of zinc, as it forms zinc sulfide. Thus, the metal `M` in the salt is **Zinc (Zn)**. ### Final Answer: The metal `M` in the salt is **Zinc (Zn)**.
To solve the problem step by step, we will analyze the information given in the question and apply our knowledge of qualitative analysis. ### Step 1: Identify the Metal Sulfate The problem states that we have a colorless metal sulfate `M` that forms a white precipitate with `NH4OH` (ammonium hydroxide). This indicates that the metal ion `M` likely forms a hydroxide that is insoluble in water. **Hint:** Look for metal ions that form insoluble hydroxides. ### Step 2: Analyze the Precipitate with NH4OH ...
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