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White precipitate of Zn(OH)(2) dissolves...

White precipitate of `Zn(OH)_(2)` dissolves in:

A

sodium hydroxide solution

B

acid solution

C

ammonia solution

D

solution of ammonium salts

Text Solution

Verified by Experts

The correct Answer is:
A,B,C,D

(A)`Zn(OH)_(2)darr+2OH^(-)to[Zn(OH)_(4)]^(2-)`
(B)`Zn(OH)_(2)darr +2H^(+) hArr Zn^(2+) + 2H_(2)O`
( C) & (D) White precipitate of `Zn(OH)_(2)` dissolves in excess of ammonia solution and in solutions of ammonium salts owing to the production of tetraamminezincate (II).
`Zn(OH)_(2)darr +4NH_(3) hArr [Zn(NH_(3))_(4)]^(2+)+2OH^(-)`
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Which of the following statements is // are correct ? (I) White precipitate of Zn(OH)_(2) is soluble in excess ammonia and in solutions of ammonium salts. (II) Yellow precipitate of barium chromate is soluble in dilute acetic acid as well as in mineral acids. (III) Green precipitate of Ni(OH)_(2) is soluble in excess sodium hydroxide.

Statement-1 :White precipitate of Mg(OH)_(2) is insoluble in excess of sodium hydroxide but readily soluble in solution of ammonium salts. Statement-2 : Mg(OH)_(2) is very sparingly soluble in water.

Knowledge Check

  • Identify (A) + N_(2) overset(Delta) rarr (B) overset(H_(2) O) rarr underset("White ppt.") ((C)darr) (D)_((g)) White precipitate ( C) dissolves is NaOH solution the gas (D) gives white fumes with HCl .

    A
    B
    B
    AI
    C
    GA
    D
    C
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