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A metal salt solution forms a yellow pre...

A metal salt solution forms a yellow precipitate with potassium chromate in acetic acid, a white precipitate with dilute `H_2 SO_4` but gives no precipitate with sodium chloride or iodide, it is

A

lead carbonate

B

basic lead carbonate

C

barium carbonate

D

strontium carbonate

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the information given about the metal salt solution and the reactions it undergoes. Let's break it down step by step. ### Step 1: Analyze the yellow precipitate with potassium chromate in acetic acid. - The metal salt solution forms a yellow precipitate when it reacts with potassium chromate (K2CrO4) in acetic acid. This indicates the formation of a chromate salt, which is typically yellow in color. **Hint:** Look for metal ions that form yellow chromates, such as barium (Ba) or lead (Pb). ### Step 2: Analyze the white precipitate with dilute H2SO4. - The same metal salt solution also forms a white precipitate when treated with dilute sulfuric acid (H2SO4). This suggests the formation of a sulfate salt, which is usually white. **Hint:** Identify metal ions that form white precipitates with sulfate ions, such as barium sulfate (BaSO4). ### Step 3: Analyze the lack of precipitate with sodium chloride or iodide. - The solution does not give any precipitate when mixed with sodium chloride (NaCl) or sodium iodide (NaI). This means that the metal salt does not form insoluble chlorides or iodides. **Hint:** Consider metal ions that are soluble in chloride and iodide solutions, which helps narrow down the options. ### Step 4: Evaluate possible metal salts. 1. **Lead Carbonate (PbCO3)**: - Forms a precipitate with NaCl (PbCl2), so it is not the correct option. 2. **Basic Lead Carbonate (PbCO3·Pb(OH)2)**: - Also forms a precipitate with NaCl, so it is incorrect. 3. **Barium Carbonate (BaCO3)**: - Forms a yellow precipitate (BaCrO4) with K2CrO4 and a white precipitate (BaSO4) with H2SO4. - It does not form a precipitate with NaCl, making this option correct. 4. **Strontium Carbonate (SrCO3)**: - Soluble in acetic acid and does not form a precipitate with NaCl, but it does not fit the criteria for the yellow precipitate. ### Conclusion: The metal salt solution is **Barium Carbonate (BaCO3)**, as it meets all the criteria: it forms a yellow precipitate with potassium chromate, a white precipitate with dilute sulfuric acid, and does not precipitate with sodium chloride or iodide. ### Final Answer: The metal salt solution is **Barium Carbonate (BaCO3)**.
To solve the problem, we need to analyze the information given about the metal salt solution and the reactions it undergoes. Let's break it down step by step. ### Step 1: Analyze the yellow precipitate with potassium chromate in acetic acid. - The metal salt solution forms a yellow precipitate when it reacts with potassium chromate (K2CrO4) in acetic acid. This indicates the formation of a chromate salt, which is typically yellow in color. **Hint:** Look for metal ions that form yellow chromates, such as barium (Ba) or lead (Pb). ### Step 2: Analyze the white precipitate with dilute H2SO4. ...
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