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CoCl(2) + KNO(2) + CH(3)COOH to [X] +H(2...

`CoCl_(2) + KNO_(2) + CH_(3)COOH to [X] +H_(2)O +KCl + CH_(3)COOK +NO`
(Unbalenced equation)

A

`X` is a yellow crystalline solid insoluble in water.

B

`X` is a green coloured compounds known as kinman's green

C

`IUPAC` name of `X` is potassium hexanitrito-`N`-cobaltate (II)

D

The compound `X` is an inner orbital complex.

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To solve the given reaction \( \text{CoCl}_2 + \text{KNO}_2 + \text{CH}_3\text{COOH} \rightarrow [X] + \text{H}_2\text{O} + \text{KCl} + \text{CH}_3\text{COOK} + \text{NO} \), we need to identify the compound \( [X] \) formed in the reaction. ### Step-by-Step Solution: 1. **Identify Reactants and Products**: - The reactants are Cobalt(II) chloride (\( \text{CoCl}_2 \)), Potassium nitrite (\( \text{KNO}_2 \)), and Acetic acid (\( \text{CH}_3\text{COOH} \)). - The products include \( [X] \), water (\( \text{H}_2\text{O} \)), Potassium chloride (\( \text{KCl} \)), Potassium acetate (\( \text{CH}_3\text{COOK} \)), and Nitric oxide (\( \text{NO} \)). 2. **Determine the Nature of Compound \( [X] \)**: - The reaction involves the formation of a coordination complex. Cobalt(II) ions can form complexes with nitrite ions. - The presence of \( \text{KNO}_2 \) suggests that the nitrite ion acts as a ligand. 3. **Write the Formula for the Complex**: - The complex formed is \( \text{K}_3[\text{Co}(\text{NO}_2)_6] \). - This complex is known as Potassium hexanitrocobaltate(II). 4. **Identify the Color and Solubility**: - The complex \( \text{K}_3[\text{Co}(\text{NO}_2)_6] \) is a yellow crystalline solid and is insoluble in water. 5. **Determine the IUPAC Name**: - The IUPAC name for the complex is Potassium hexanitrocobaltate(II). 6. **Final Conclusion**: - Therefore, the compound \( [X] \) is \( \text{K}_3[\text{Co}(\text{NO}_2)_6] \), which is a yellow crystalline solid and an inner orbital complex. ### Final Answer: - The answer is \( [X] = \text{K}_3[\text{Co}(\text{NO}_2)_6] \) (Potassium hexanitrocobaltate(II)), which is a yellow crystalline solid and an inner orbital complex.

To solve the given reaction \( \text{CoCl}_2 + \text{KNO}_2 + \text{CH}_3\text{COOH} \rightarrow [X] + \text{H}_2\text{O} + \text{KCl} + \text{CH}_3\text{COOK} + \text{NO} \), we need to identify the compound \( [X] \) formed in the reaction. ### Step-by-Step Solution: 1. **Identify Reactants and Products**: - The reactants are Cobalt(II) chloride (\( \text{CoCl}_2 \)), Potassium nitrite (\( \text{KNO}_2 \)), and Acetic acid (\( \text{CH}_3\text{COOH} \)). - The products include \( [X] \), water (\( \text{H}_2\text{O} \)), Potassium chloride (\( \text{KCl} \)), Potassium acetate (\( \text{CH}_3\text{COOK} \)), and Nitric oxide (\( \text{NO} \)). ...
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RESONANCE ENGLISH-QUALITATIVE ANALYSIS PART 1-A.L.P
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