What happen when `4`-nitrobenzene diazonium chloride reagent reacts with an ammonium salt in the presence of sodium hydroxide solution ?

Explanation

To understand what happens when 4-nitrobenzene diazonium chloride reacts with an ammonium salt in the presence of sodium hydroxide solution, we can break down the reaction step-by-step:

### Step 1: Identify the Reactants
The reactants in this reaction are:
- 4-nitrobenzene diazonium chloride (C6H4(N2Cl)(NO2))
- Ammonium salt (NH4+)
- Sodium hydroxide (NaOH)

### Step 2: Understand the Nature of the Reaction
4-nitrobenzene diazonium chloride is a diazonium salt that can undergo nucleophilic substitution reactions. In this case, the ammonium ion (NH4+) acts as a nucleophile.

### Step 3: Reaction Mechanism
In the presence of sodium hydroxide, which provides an alkaline medium, the diazonium ion (N2+) can react with the ammonium ion. The hydroxide ions (OH-) from sodium hydroxide can also facilitate the reaction by stabilizing the intermediate formed.

### Step 4: Formation of the Product
The reaction leads to the formation of a compound where the diazonium group is replaced by an amine group:
- The nitrogen in the diazonium ion (N2+) is replaced by the ammonium ion (NH4+), resulting in the formation of a red-colored compound, which can be represented as:
- N=N-O-NH4+ + Cl- + H2O

### Step 5: Observation
The solution will appear red due to the formation of the product, which is a colored compound.

### Summary of the Reaction
When 4-nitrobenzene diazonium chloride reacts with an ammonium salt in the presence of sodium hydroxide, it forms a red-colored compound, releasing chloride ions and water in the process.

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