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Draw formulae for the first four members...

Draw formulae for the first four members of each homologous series begining with the following.
(a)`H-COOH` , (b)`H-CH=CH_(2)` , (c )`CH_(3)-oversetoverset(O)(||)(C)-CH_(3)`

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To solve the question, we need to draw the formulae for the first four members of each homologous series starting with the given compounds: ### (a) Starting with `H-COOH` (Formic Acid - Carboxylic Acid) 1. **First Member**: - Formula: `HCOOH` (Formic Acid) 2. **Second Member**: - Add one carbon atom (methyl group) to the first member. - Formula: `CH3COOH` (Acetic Acid) 3. **Third Member**: - Add another carbon atom to the second member. - Formula: `CH3CH2COOH` (Propanoic Acid) 4. **Fourth Member**: - Add one more carbon atom to the third member. - Formula: `CH3CH2CH2COOH` (Butanoic Acid) ### Summary for (a): - 1st: `HCOOH` (Formic Acid) - 2nd: `CH3COOH` (Acetic Acid) - 3rd: `CH3CH2COOH` (Propanoic Acid) - 4th: `CH3CH2CH2COOH` (Butanoic Acid) --- ### (b) Starting with `H-CH=CH2` (Ethylene - Alkene) 1. **First Member**: - Formula: `H2C=CH2` (Ethylene) 2. **Second Member**: - Add one carbon atom (methyl group) to the first member. - Formula: `CH3CH=CH2` (Propene) 3. **Third Member**: - Add another carbon atom to the second member. - Formula: `CH3CH2CH=CH2` (Butene) 4. **Fourth Member**: - Add one more carbon atom to the third member. - Formula: `CH3CH2CH2CH=CH2` (Pentene) ### Summary for (b): - 1st: `H2C=CH2` (Ethylene) - 2nd: `CH3CH=CH2` (Propene) - 3rd: `CH3CH2CH=CH2` (Butene) - 4th: `CH3CH2CH2CH=CH2` (Pentene) --- ### (c) Starting with `CH3-C(=O)-CH3` (Propanone - Ketone) 1. **First Member**: - Formula: `CH3C(=O)CH3` (Propanone) 2. **Second Member**: - Add one carbon atom to the first member. - Formula: `CH3CH2C(=O)CH3` (Butanone) 3. **Third Member**: - Add another carbon atom to the second member. - Formula: `CH3CH2CH2C(=O)CH3` (Pentanone) 4. **Fourth Member**: - Add one more carbon atom to the third member. - Formula: `CH3CH2CH2CH2C(=O)CH3` (Hexanone) ### Summary for (c): - 1st: `CH3C(=O)CH3` (Propanone) - 2nd: `CH3CH2C(=O)CH3` (Butanone) - 3rd: `CH3CH2CH2C(=O)CH3` (Pentanone) - 4th: `CH3CH2CH2CH2C(=O)CH3` (Hexanone) ---

To solve the question, we need to draw the formulae for the first four members of each homologous series starting with the given compounds: ### (a) Starting with `H-COOH` (Formic Acid - Carboxylic Acid) 1. **First Member**: - Formula: `HCOOH` (Formic Acid) 2. **Second Member**: ...
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