The `IUPAC` name of
`CH_(3)-undersetunderset(OH)(|)(CH)-CH_(2)-CH_(2)-CH_(2)-undersetunderset(Br)(|)oversetoverset(Br)(|)(C)-CH_(3)` is:

Options

A. `6,6`-Dibromoheptan-`2`-ol
B. `2,2`-Dibromoheptane-`6`-ol
C. `6,6`-Dibromoheptan-`2`-al
D. None of these

Answer

To determine the IUPAC name of the given compound, we will follow these steps:

### Step 1: Identify the longest carbon chain
The longest carbon chain in the compound has 7 carbon atoms. This is known as a heptane.

### Step 2: Identify and prioritize functional groups
In this compound, we have an alcohol group (-OH) and two bromine substituents (Br). According to IUPAC nomenclature rules, the alcohol group has a higher priority than the bromine substituents.

### Step 3: Number the carbon chain
We will number the carbon chain from the end nearest to the alcohol group to give it the lowest possible number. This means we will number from left to right:
- Carbon 1: CH3
- Carbon 2: OH (alcohol)
- Carbon 3: CH
- Carbon 4: CH2
- Carbon 5: CH2
- Carbon 6: CH (with two Br substituents)
- Carbon 7: CH3

### Step 4: Assign locants to the substituents
- The alcohol group (-OH) is on carbon 2, so we denote it as 2-ol.
- The two bromine substituents are both on carbon 6, so we denote them as 6,6-dibromo.

### Step 5: Combine the names and write the final IUPAC name
Putting it all together, we have:
- The base name is "heptane" (7 carbon atoms).
- The substituents are "6,6-dibromo" and the functional group is "2-ol".

Thus, the complete IUPAC name of the compound is:
**6,6-dibromo-2-heptanol**