`IUPAC` name of the compound `BrCH_(2)-undersetunderset(CONH_(2))(|)(CH)-CO-CH_(2)-CH_(2)CH_(3)` is

Options

A. `2`-Bromomethyl-`3`-oxohexanamide
B. `1`-Bromo-`2`-amido-`3`-oxohexane
C. `1`-Bromo-`2`-amido-n-propylketone
D. `3`-Bromo-`2`-proponyl-propanamide

Answer

To determine the IUPAC name of the compound `BrCH₂-CO-NH₂-(CH)-CO-CH₂-CH₂-CH₃`, we will follow a systematic approach to identify the longest carbon chain, the functional groups, and their positions.

### Step-by-Step Solution:

1. **Identify the Functional Groups**:
- The compound has three functional groups:
- An amide group (–CO–NH₂)
- A keto group (C=O)
- A bromo group (Br)

2. **Determine the Priority of Functional Groups**:
- According to IUPAC nomenclature, the priority order of functional groups is as follows:
1. Amide (highest priority)
2. Ketone (C=O)
3. Bromo (lowest priority)

3. **Identify the Longest Carbon Chain**:
- The longest continuous carbon chain that includes the amide group is 6 carbons long. We will number the chain starting from the end closest to the amide group.
- The longest chain can be represented as:
- C1 - C2 - C3 - C4 - C5 - C6

4. **Number the Carbon Chain**:
- Numbering from the end nearest to the amide group:
- C1: Amide group (–CO–NH₂)
- C2: Bromo group (Br)
- C3: Keto group (C=O)

5. **Assign Substituents and Their Positions**:
- At C2, there is a bromo substituent (BrCH₂), which is referred to as bromomethyl.
- At C3, there is a keto group, which is indicated by the prefix "oxo".

6. **Construct the Name**:
- The base name for the 6-carbon chain is "hexane".
- Since the primary functional group is an amide, the suffix will be "amide".
- Combine the substituents with their positions:
- 2-bromomethyl (from the bromo substituent)
- 3-oxo (from the keto group)

7. **Final IUPAC Name**:
- Combine all parts to form the complete name:
- The IUPAC name of the compound is **2-bromomethyl-3-oxohexanamide**.

### Final Answer:
**2-bromomethyl-3-oxohexanamide**