Total number of `2^(@)` amine isomers of `C_(4)H_(11)N` would be (only structural)

Options

A. 4
B. 3
C. 5
D. 2

Answer

To determine the total number of structural isomers for the compound C₄H₁₁N that are classified as secondary amines, we can follow these steps:

### Step 1: Understand the structure of secondary amines
Secondary amines have the general structure R₂NH, where R represents alkyl groups. In this case, we need to find isomers where the nitrogen atom is bonded to two carbon atoms and one hydrogen atom.

### Step 2: Identify the molecular formula
The molecular formula given is C₄H₁₁N. This indicates that we have four carbon atoms, eleven hydrogen atoms, and one nitrogen atom to work with.

### Step 3: Determine the possible carbon skeletons
We can create different carbon skeletons using four carbon atoms. The possible arrangements include:
1. A straight-chain (butane)
2. Branched chains (isobutane)

### Step 4: Generate structural isomers
Now, we will generate the structural isomers based on the carbon skeletons identified:

1. **Butan-2-amine** (straight-chain):
- Structure: CH₃-CH(NH)-CH₂-CH₃

2. **2-Methylpropan-2-amine** (branched):
- Structure: (CH₃)₂C(NH)(CH₃)

3. **1-Methylpropan-1-amine** (branched):
- Structure: CH₃-CH₂-CH(NH)-CH₃

### Step 5: Count the isomers
From the structures generated, we can see that there are three distinct structural isomers of C₄H₁₁N that are classified as secondary amines.

### Conclusion
Thus, the total number of structural isomers of secondary amines for C₄H₁₁N is **3**.

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