The `IUPAC` name of compound `CH_(3)-C(CH_(3))_(2)-CH_(2)-CH=CH_(2)` is

Options

A. `2,2`-Dimethylpent-`4`-ene
B. `2,2`-Dimethyl-`2`-pentene
C. `1,1,1`-Trimethylbut-`3`-ene
D. `4,4`-Dimethylpent-`1`-ene

Answer

To determine the IUPAC name of the compound \( CH_3-C(CH_3)_2-CH_2-CH=CH_2 \), we can follow these steps:

### Step 1: Identify the Longest Carbon Chain
First, we need to identify the longest continuous carbon chain in the compound. In this case, the longest chain contains 5 carbon atoms.

### Step 2: Number the Carbon Chain
Next, we will number the carbon chain. We start numbering from the end closest to the double bond to give the double bond the lowest possible number. The numbering will be as follows:

1. \( CH_2 \) (1)
2. \( CH \) (2)
3. \( C \) (3)
4. \( C \) (4)
5. \( C \) (5)

This gives us a structure of pentene, since there are 5 carbons and a double bond.

### Step 3: Identify Substituents
Now, we need to identify any substituents on the main chain. In this compound, there are two methyl groups attached to the second carbon of the chain.

### Step 4: Assign Locants to Substituents
The two methyl groups are located at carbon 2. Therefore, we will denote this as "2,2-dimethyl".

### Step 5: Identify the Position of the Double Bond
The double bond is located between carbon 4 and carbon 5. Therefore, we indicate the position of the double bond as "pent-4-ene".

### Step 6: Combine All Parts for the IUPAC Name
Now, we can combine all the parts to write the full IUPAC name. The final name will be:

**2,2-dimethylpent-4-ene**

### Final Answer
The IUPAC name of the compound \( CH_3-C(CH_3)_2-CH_2-CH=CH_2 \) is **2,2-dimethylpent-4-ene**.

---