Me-O-C(Me)=O and Et -O-CH=O are :

Options

A. Functional Isomers
B. Metamers
C. Positional isomers
D. Chain isomers

Answer

To determine the relationship between the two given compounds, Me-O-C(Me)=O and Et-O-CH=O, we will follow these steps:

### Step 1: Identify the Structures
First, we need to draw the structures of the two compounds based on their given formulas.

- For Me-O-C(Me)=O:
- The structure can be represented as:
```
O
||
Me-O-C
|
Me
```
- This represents methyl acetate (or methyl ethanoate).

- For Et-O-CH=O:
- The structure can be represented as:
```
O
||
Et-O-CH
```
- This represents ethyl formate (or ethyl methanoate).

### Step 2: Analyze the Functional Groups
Next, we need to identify the functional groups present in both compounds.

- Both compounds contain the ester functional group (-O-C=O).
- The first compound has a methyl group (Me) and a carbonyl (C=O) attached to it.
- The second compound has an ethyl group (Et) and a carbonyl (C=O) attached to it.

### Step 3: Compare Molecular Formulas
Now we will determine if the two compounds have the same molecular formula.

- For Me-O-C(Me)=O (Methyl acetate):
- The molecular formula is C3H6O2.

- For Et-O-CH=O (Ethyl formate):
- The molecular formula is also C3H6O2.

### Step 4: Determine the Type of Isomerism
Since both compounds have the same molecular formula but different alkyl groups attached to the functional group, we classify them based on the type of isomerism.

- The isomerism where compounds have the same molecular formula but differ in the arrangement of alkyl groups around the functional group is known as **Metamers**.

### Conclusion
Thus, the two compounds Me-O-C(Me)=O and Et-O-CH=O are **Metamers**.

### Final Answer
The correct option is **B: Metamers**.

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