The `C-C-H` bond angle in ethylene is:

Options

A. `180^(@)`
B. `109^(@)28^(@)`
C. `120^(@)`
D. `90^(@)`

Answer

To find the C-C-H bond angle in ethylene (C2H4), we can follow these steps:

### Step 1: Draw the Structure of Ethylene
Ethylene has the molecular formula C2H4. The structure consists of two carbon atoms connected by a double bond, with each carbon atom bonded to two hydrogen atoms.

**Structure:**
```
H H
\ /
C = C
/ \
H H
```

### Step 2: Identify the Bond Angles
In ethylene, we are interested in the C-C-H bond angle. Since the structure is symmetrical, all C-C-H bond angles will be the same.

### Step 3: Understand the Geometry
Ethylene has a planar structure due to the presence of the double bond between the carbon atoms. The geometry around each carbon atom is trigonal planar.

### Step 4: Calculate the Bond Angle
In a trigonal planar arrangement, the bond angles are all equal. The total angle around a carbon atom is 360 degrees, and since there are three bonds (two C-H bonds and one C-C bond), we can divide the total angle by the number of bonds to find the bond angle.

- Total angle = 360 degrees
- Number of angles (bonds) = 3 (C-H, C-H, and C-C)

Using the formula:
\[ \text{Bond angle} = \frac{360^\circ}{3} = 120^\circ \]

### Conclusion
The C-C-H bond angle in ethylene is 120 degrees.

### Final Answer
The C-C-H bond angle in ethylene is **120 degrees**.

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