In the following sequence of reactions, the alkene affords the compound `'B'`
`CH_(3)CH=CHCH_(3)overset(O_(3))rarrAoverset(H_(2)O)rarrB` compound `B` is :

Options

A. `CH_(3)CH_(3)CHO`
B. `CH_(3)COCH_(3)`
C. `CH_(3)CH_(2)COCH_(3)`
D. `CH_(3)CHO`

Explanation

To determine the compound B formed from the given alkene through the specified reactions, we can follow these steps:

### Step 1: Identify the Alkene
The alkene provided is **CH₃CH=CHCH₃**. This is 2-butene.

### Step 2: Ozonolysis of the Alkene
When 2-butene undergoes ozonolysis (reaction with ozone, O₃), it cleaves the double bond and forms an intermediate ozonide. The ozonolysis of 2-butene results in the formation of two carbonyl compounds.

### Step 3: Structure of the Intermediate (Compound A)
The ozonolysis of 2-butene will yield an ozonide that can be represented as:
- The double bond between the second and third carbon atoms will break, leading to the formation of two aldehyde groups.

### Step 4: Hydrolysis of the Ozonide
Upon hydrolysis (reaction with water, H₂O), the ozonide will be converted into carbonyl compounds. In this case, the ozonide will yield:
- 2 molecules of **acetaldehyde (CH₃CHO)**.

### Step 5: Identify Compound B
Thus, the final product B after ozonolysis and hydrolysis of 2-butene is:
- **Compound B = CH₃CHO (acetaldehyde)**.

### Conclusion
The compound B formed from the given alkene through the specified reactions is **acetaldehyde (CH₃CHO)**.

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