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In Carius method of estimation of haloge...

In Carius method of estimation of halogens, 250 mg of an organic compound gave 141 mg of `AgBr`. The percentage of bromine in the compound is: (at. Mass Ag = 108, Br = 80)

A

`24`

B

`36`

C

`48`

D

`60`

Text Solution

Verified by Experts

The correct Answer is:
A

`% X = ("Atomic mass of Br")/("Molecular mass of AgBr") xx ("Wt. of AgBr")/("Wt. of organic Bromide")`
Thus `% Br = (80)/(188) xx (141)/(250) xx 100 = 24`.
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