A hydrogen on oxidative ozonlysis produces Oxalic acid and Butanedioic acid. Its structrure is

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Explanation

To determine the structure of the hydrogen compound that, upon oxidative ozonolysis, yields oxalic acid and butanedioic acid, we can follow these steps:

### Step 1: Understand the Products
The products of the oxidative ozonolysis are oxalic acid (C2H2O4) and butanedioic acid (C4H6O4).
- Oxalic acid has the structure: HOOC-COOH
- Butanedioic acid has the structure: HOOC-CH2-CH2-COOH

### Step 2: Analyze the Carbon Count
- Oxalic acid has 2 carbon atoms.
- Butanedioic acid has 4 carbon atoms.
- Therefore, the starting compound must have a total of 6 carbon atoms (2 from oxalic acid + 4 from butanedioic acid).

### Step 3: Determine the Structure of the Starting Compound
To produce these acids through ozonolysis, the starting compound must have a structure that allows for cleavage into these products. A likely candidate is a symmetrical compound with a double bond that can be cleaved.

### Step 4: Propose a Possible Structure
A suitable structure for the starting compound could be 2,4-hexadiene (CH2=CH-CH=CH2). This compound has 6 carbon atoms and two double bonds.

### Step 5: Predict the Ozonolysis Reaction
When 2,4-hexadiene undergoes oxidative ozonolysis:
1. The double bonds will break, leading to the formation of carbonyl groups (C=O).
2. Each carbon that was part of a double bond will be converted to a carbonyl (C=O) and will also have a hydroxyl (OH) group added.

### Step 6: Identify the Final Products
The ozonolysis of 2,4-hexadiene would yield:
- Two molecules of oxalic acid (from the cleavage of the double bonds at the ends).
- One molecule of butanedioic acid (from the central part of the molecule).

### Conclusion
Thus, the structure of the hydrogen compound that produces oxalic acid and butanedioic acid upon oxidative ozonolysis is 2,4-hexadiene.