Home
Class 12
PHYSICS
The average value of current i=I(m) sin ...

The average value of current `i=I_(m) sin omega t from t=(pi)/(2 omega )` to `t=(3 pi)/(2 omega)` si how many times of `(I_m)`?

Text Solution

Verified by Experts

`l_(rms) =sqrt((underset(0)overset((2pi)/omega)int I_(m)^(2)sin ^(2)omega t dt)/((2pi)/omega))=sqrt(I_(m)^(2)/2)=I_(m)/sqrt2`
Promotional Banner

Similar Questions

Explore conceptually related problems

Find the rms value of current i=I_(m)sin omegat from (i) t=0 "to" t=(pi)/(omega) (ii) t=(pi)/(2omega) "to" t=(3pi)/(2omega)

r.m.s. value of current i=3+4 sin (omega t+pi//3) is:

The average value of alternating current I=I_(0) sin omegat in time interval [0, pi/omega] is

If i_(1)=3 sin omega t and (i_2) = 4 cos omega t, then (i_3) is

The voltage over a cycle varies as V=V_(0)sin omega t for 0 le t le (pi)/(omega) =-V_(0)sin omega t for (pi)/(omega)le t le (2pi)/(omega) The average value of the voltage one cycle is

The voltage over a cycle varies as V=V_(0)sin omega t for 0 le t le (pi)/(omega) =-V_(0)sin omega t for (pi)/(omega)le t le (2pi)/(omega) The average value of the voltage one cycle is

Find the rms value of current from t = 0 to t=(2pi)/omega if the current varies as i=I_(m)sin omegat .

Find the rms value of current from t=0 to t= (2pi)/(omega) if the current avries as i=I_(m)sin omegat .

Find the rms value of current from t=0 to t= (2pi)/(omega) if the current avries as i=I_(m)sin omegat .

In y= A sin omega t + A sin ( omega t+(2 pi )/3) match the following table.