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A bulb is rated at 100V, 100W. It can be...

A bulb is rated at `100V`, `100W`. It can be treated as a resistor. Find out the inductance of an inductor (called choke coil) that should be connected in series with the bulb at its rated power with the help of an ac source of `200V` and `50Hz`.

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From the rating of the bulb, the resistance of the bulb is `R=V_(rms)/P=100 Omega`
For the bulb to be operated at its rated value the `rms` current through it should be `1A`
Also,`I_(rms)=V_(rms)/Z`
`therefore 1=200/sqrt(100^(2)+(2pi50L)^(2)) L=sqrt3/pi=H`
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