The current in a discharging `LR` circuit is given by `I = i_0 e^(-t/tau)` where `tau` is the time constant of the circuit. Calculate the rms current for the period `t = 0` to `t = tau`.

The current in a discharging LR circuit is given by I = i_0 (t/tau) where tau is the time constant of the circuit. Calculate the rms current for the period t = 0 to t = tau .

The electric curren in a charging R-C circuit is given by i=i_0e^(-t/RC) when i_0 , R and C aere constant parameters of the circuit and t is time. Find the rate of change of current at a. t=0, b. t=RC c. t=10RC .

The current in a discharging LR circuit without the battery drops from 2.0 A to 1.0A in 0.10 s. (a) find the time constant of the circuit. (b) if the inductance of the circuit is 4.0 H, what is its resistance?

The electric current in a discharging R-C circuit is given by i=i_0e^(-t/(RC)) where i_0 R and C are constant parameters and t is time. Let i_0=2.00A , R=6.00xx10^5 ohm and C=0.500 muF . a. Find the current at t=0.3 s. b. Find the rate of change of current at t=0.3 s. Find approximately the current at t=0.31 s.

The current in an AC circuit is given by I = I_0 sin (50 pi )/t where t is in second. The time interval in which it will reach from zero to its peak value is

Current in an ac circuit is given by I= 3 sin omega t + 4 cos omega t, then

The electric current in a circuit is given by i=3t Here, t is in second and I in ampere. The rms current for the period to=0 to t=1 s is

The voltage supplied to a circuit is given by V=V_(0)t^(3/2) , where t is time in second. Find the rms value of voltage for the period, t=0 to t=1s.

In an LR circuit, current at t=0 is 20A . After 2s it reduced to 18A. The time constant of the circuit is (in second)

Show that time constant (tau = RC) of R - C circuit has the dimensions of time.