A pure resistive circuit element X when connected to an AC supply of peak voltage 200 V, gives a peak current of 5 A . A second circuit element Y , when connected to the same AC supply also gives the same value of peak current but the current lags behind by `90^(@)` . If the series combination X and Y is connnected to the same supply, what be the rms value of current?

Options

A. `10/sqrt2` amp
B. `5/sqrt2` amp
C. `5/2` amp
D. `5` amp

Answer

C

Explanation

`R=V_(0)/I_(0)=200/5=40 Omega`(For circuit `x`)
`X=V_(0)/I_(0)=40 Omega`(For circuit `y`)
if `x` & `y` are in series
`I=200/(40xxsqrt2)=5/sqrt2A`Amp. `rArr=I_(rms)=I_(0)/sqrt2=5/2` amp.