In a step-up transformer the voltage in the primary is `220 V` and the currrent is `5A`. The secondary voltage is found to be `22000V`. The current in the secondary (neglect losses)is

Options

A. `5 A`
B. `50 A`
C. `500 A`
D. `0.05 A`

Explanation

To find the current in the secondary of a step-up transformer, we can use the relationship between the primary and secondary voltages and currents. The formula we will use is:

\[ \frac{V_p}{V_s} = \frac{I_s}{I_p} \]

Where:
- \( V_p \) = Primary voltage
- \( V_s \) = Secondary voltage
- \( I_p \) = Primary current
- \( I_s \) = Secondary current

Given:
- \( V_p = 220 \, V \)
- \( I_p = 5 \, A \)
- \( V_s = 22000 \, V \)

We need to find \( I_s \).

### Step 1: Substitute the known values into the formula

\[ \frac{220}{22000} = \frac{I_s}{5} \]

### Step 2: Simplify the left side of the equation

\[ \frac{220}{22000} = \frac{1}{100} \]

### Step 3: Set up the equation

Now, we can rewrite the equation as:

\[ \frac{1}{100} = \frac{I_s}{5} \]

### Step 4: Cross-multiply to solve for \( I_s \)

\[ I_s = 5 \times \frac{1}{100} \]

### Step 5: Calculate \( I_s \)

\[ I_s = \frac{5}{100} = 0.05 \, A \]

Thus, the current in the secondary is \( 0.05 \, A \).

### Final Answer:
The current in the secondary is \( 0.05 \, A \).

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