Home
Class 12
PHYSICS
In an a.c. circuit consisting of resista...

In an `a.c.` circuit consisting of resistance `R` and inductance `L`, the voltage across `R` is `60` volt and that across `L` is `80` volt.The total voltage across the combination is

A

`140 V`

B

`20 V`

C

`100 V`

D

`70 V`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the total voltage across a combination of resistance (R) and inductance (L) in an AC circuit. The voltages across the resistor (V_R) and the inductor (V_L) are given as follows: - Voltage across the resistor, \( V_R = 60 \, \text{V} \) - Voltage across the inductor, \( V_L = 80 \, \text{V} \) ### Step 1: Understand the relationship between voltages in an R-L circuit In an R-L circuit, the total voltage (V) across the combination is given by the vector sum of the voltages across the resistor and the inductor. This is because the voltages are not in phase; the voltage across the resistor is in phase with the current, while the voltage across the inductor lags the current by 90 degrees. ### Step 2: Use the Pythagorean theorem The total voltage can be calculated using the Pythagorean theorem: \[ V = \sqrt{V_R^2 + V_L^2} \] ### Step 3: Substitute the values Now, we substitute the given values into the equation: \[ V = \sqrt{(60 \, \text{V})^2 + (80 \, \text{V})^2} \] ### Step 4: Calculate \( V_R^2 \) and \( V_L^2 \) Calculating the squares: \[ V_R^2 = 60^2 = 3600 \, \text{V}^2 \] \[ V_L^2 = 80^2 = 6400 \, \text{V}^2 \] ### Step 5: Add the squares Now, add these two results: \[ V_R^2 + V_L^2 = 3600 + 6400 = 10000 \, \text{V}^2 \] ### Step 6: Take the square root Finally, we take the square root to find the total voltage: \[ V = \sqrt{10000} = 100 \, \text{V} \] ### Conclusion The total voltage across the combination of resistance and inductance is: \[ \boxed{100 \, \text{V}} \]
Promotional Banner

Topper's Solved these Questions

  • ALTERNATING CURRENT

    RESONANCE ENGLISH|Exercise Exercise -2 Part-1|14 Videos
  • ALTERNATING CURRENT

    RESONANCE ENGLISH|Exercise Exercise -2 Part-2|6 Videos
  • ALTERNATING CURRENT

    RESONANCE ENGLISH|Exercise HIGH LEVEL PROBLEMS|11 Videos
  • ATOMIC PHYSICS

    RESONANCE ENGLISH|Exercise Advanved level problems|17 Videos

Similar Questions

Explore conceptually related problems

A 20volts AC is applied to a circuit consisting of a resistance and a coil with negligible resistance. If the voltage across the resistance is 12V , the voltage across the coil is

In an LCR series ac circuit , the voltage across each of the components , L,C and R is 50 V . The voltage across the LC combination will be :

In an L-C-R circuit the AC voltage across R, L and C comes out as 10 V , 10 V and 20 V respectively . The voltage across the enter combination will be

A coil of resistance R and inductance L is connected across an a.c power supply of r.m.s. voltage V. The average power dissipated in the coil is,

In the given circuit , the voltage across the base emitter junction is

An alternating voltage is connected in series with a resistance R and inductance L if the potential drop across the resistance is 200V and across the inductance is 150V , then the applied voltage is

The circuit given in fig. has a resistanceless choke coil L and a resistance R. The voltage across R and L are also given in the figure. The virtual value of the applied voltage is

In a series resonant circuit, the ac, voltage across resistance R, inductance L and capacitance are 5V, 10V and 10V, respectively. The ac. voltage applied to the circuit will be

In series LCR circuit, the voltages across R, L and C are shown in the figure. The voltage of applied source

In series LCR circuit, the phase difference between voltage across L and voltage across C is

RESONANCE ENGLISH-ALTERNATING CURRENT-Exercise -1 Part-1
  1. An alternating voltage E=200sqrt(2)sin(100t) is connected to a 1 micro...

    Text Solution

    |

  2. When 100 V DC is applied across a solenoid, a steady current of 1 A fl...

    Text Solution

    |

  3. In an L-C-R circuit the AC voltage across R, L and C comes out as 10 V...

    Text Solution

    |

  4. In the series L-C-R circuit , the voltmeter and ammeter readings are

    Text Solution

    |

  5. For a series LCR circuit the power loss at resonance is : -

    Text Solution

    |

  6. A series LCR circuit containing a resistance of 120 ohm has angular re...

    Text Solution

    |

  7. In an LCR circuit, the capacitance is made one-fourth, when in resonan...

    Text Solution

    |

  8. An inductance L , a capacitor of 20muF and a resistor of 10Omega are c...

    Text Solution

    |

  9. A resistor R, an inductor L, a capacitor C and voltmeters V(1),V(2) an...

    Text Solution

    |

  10. A power transformer (step up) with an 1:8 turns ratio has 60 Hz,120 V ...

    Text Solution

    |

  11. A trensformer is used to light 140 W, 24 V lamp from a 240 V ac mains...

    Text Solution

    |

  12. In a step-up transformer the voltage in the primary is 220 V and the c...

    Text Solution

    |

  13. The core of a transformer is laminated to reduce

    Text Solution

    |

  14. A capacitor is a perfect insulator for

    Text Solution

    |

  15. A choke coil has

    Text Solution

    |

  16. A choke coil is preferred to a rheostate in AC circuit as

    Text Solution

    |

  17. With increase in frequency of an AC supply, the inductive reactance:

    Text Solution

    |

  18. With increase in frequency of an AC supply, the capacitive reactance:

    Text Solution

    |

  19. An AC ammeter is used to measure current is a circuit . When a given d...

    Text Solution

    |

  20. In an a.c. circuit consisting of resistance R and inductance L, the vo...

    Text Solution

    |