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A series R-C combination is connected to...

A series R-C combination is connected to an AC voltage of angular frequency `omega=500 radian//s`. If the impendance of the R-C circuit is `Rsqrt(1.25)`, the time constant (in millisecond) of the circuit is

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To solve the problem, we need to find the time constant of a series R-C circuit connected to an AC voltage source. The given data includes the angular frequency \( \omega = 500 \, \text{rad/s} \) and the impedance \( Z = R \sqrt{1.25} \). ### Step-by-Step Solution: 1. **Understanding Impedance in R-C Circuit**: The impedance \( Z \) of a series R-C circuit is given by the formula: \[ Z = \sqrt{R^2 + X_C^2} \] where \( X_C \) is the capacitive reactance given by \( X_C = \frac{1}{\omega C} \). 2. **Substituting Given Values**: We know that \( Z = R \sqrt{1.25} \). Therefore, we can equate the two expressions for impedance: \[ R \sqrt{1.25} = \sqrt{R^2 + \left(\frac{1}{\omega C}\right)^2} \] 3. **Squaring Both Sides**: To eliminate the square root, we square both sides: \[ R^2 \cdot 1.25 = R^2 + \left(\frac{1}{\omega C}\right)^2 \] 4. **Rearranging the Equation**: Rearranging gives us: \[ 1.25 R^2 - R^2 = \left(\frac{1}{\omega C}\right)^2 \] Simplifying this results in: \[ 0.25 R^2 = \left(\frac{1}{\omega C}\right)^2 \] 5. **Expressing \( C \)**: From the equation above, we can express \( C \): \[ \left(\frac{1}{\omega C}\right)^2 = 0.25 R^2 \] Taking the square root: \[ \frac{1}{\omega C} = 0.5 R \] Therefore: \[ C = \frac{1}{0.5 R \omega} = \frac{2}{R \omega} \] 6. **Finding the Time Constant**: The time constant \( \tau \) of an R-C circuit is given by: \[ \tau = R \cdot C \] Substituting \( C \): \[ \tau = R \cdot \frac{2}{R \omega} = \frac{2}{\omega} \] 7. **Substituting the Value of \( \omega \)**: Now substituting \( \omega = 500 \, \text{rad/s} \): \[ \tau = \frac{2}{500} = 0.004 \, \text{seconds} \] 8. **Converting to Milliseconds**: To convert seconds to milliseconds: \[ \tau = 0.004 \times 1000 = 4 \, \text{milliseconds} \] ### Final Answer: The time constant of the circuit is \( \tau = 4 \, \text{milliseconds} \).

To solve the problem, we need to find the time constant of a series R-C circuit connected to an AC voltage source. The given data includes the angular frequency \( \omega = 500 \, \text{rad/s} \) and the impedance \( Z = R \sqrt{1.25} \). ### Step-by-Step Solution: 1. **Understanding Impedance in R-C Circuit**: The impedance \( Z \) of a series R-C circuit is given by the formula: \[ Z = \sqrt{R^2 + X_C^2} ...
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