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Current in a coil of self-inductance 2.0...

Current in a coil of self-inductance `2.0 H` is increasing as `I = 2 sin wt^(2)`. The amount of energy spent during the period when the current changes from `0` to `2 A` is

Text Solution

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The correct Answer is:
`4` joule
`DU=U_(f)-U_(i)`
`=1/2(l_(1)^(2)-l_(1)^(2))=4 J`
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Knowledge Check

  • A current of 1 A through a coil of inductance of 200 mH is increasing at a rate of 0.5As^(-1) . The energy stored in the inductor per second is

    A
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    B
    `5.0Js^(-1)`
    C
    `0.1Js^(-1)`
    D
    `2.0Js^(-1)`

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