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An inductor 20xx10^(-3) a capacitor 100(...

An inductor `20xx10^(-3)` a capacitor `100(mu)F` and a resistor `50 Omega` are connected in series across a source of emf `V=10 sin 314 t`.
If resistance is removed from the circuit and the value of inductance is doubled, the variation of current with time in the new circuit is

Text Solution

Verified by Experts

The correct Answer is:
`951.52 J;0.52 cos 314 t`
Given that
`L=20xx10^(-3) H`
`C=100xx10^(-6) F`
`R=50 Omega , omega=314`
`V=10 sin 314 t , Deltat=20xx60` second
(i)`DeltaH=I_(rms)^(2)R(Deltat)=(V_(0)/(sqrt2 Z))^(2) RxxDeltat`
here `z=sqrt(R^(2)+(omegaL-1/(omegac))^(2))=sqrt((50)^(2)+(6.28-31.8)^(2))=56.15 Omega`
(ii)`I=I_(0)sin (314t+pi//2)` where `I_(0)=V_(0)/((omega(2L)-1/(omegac)))`
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