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In Young's double slit experiment intens...

In Young's double slit experiment intensity at a point is `((1)/(4))` of the maximum intensity. Angular position of this point is

A

`sin^(-1) ((lambda)/(d))`

B

`sin^(-1) ((lambda)/(3d))`

C

`sin^(-1) ((lambda)/(2d))`

D

`sin^(-1) ((lambda)/(4d))`

Text Solution

Verified by Experts

The correct Answer is:
B
Intensity of one slit `=(I)/(4)`
`therefore (I)/(4)=(I)/(4)+(I)/(4)+2(I)/(4) cos phi rArr cosphi=-(1)/(2) rArr phi=(2pi)/(3)`
Also `(phi)/(2pi)=(Delta)/(lambda) rArr Delta=(2pi)/(3xx2pi)xxlambda=(lambda)/(3)`
`therefore d sin theta=(lambda)/(3) rArr sintheta=(lambda)/(3d) rArr theta=sin^(-1)((lambda)/(3d))`
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