In a Young's double slit experiment , the slits are Kept `2mm` apart and the screen is positioned `140 cm` away from the plane of the slits. The slits are illuminatedd with light of wavelength `600 nm.` Find the distance of the third brite fringe. From the central maximum . in the interface pattern obtained on the screen frings from the central maximum. `3`

Explanation

To find the distance of the third bright fringe from the central maximum in a Young's double slit experiment, we can follow these steps:

### Step 1: Gather the given data
- Wavelength of light, \( \lambda = 600 \, \text{nm} = 600 \times 10^{-9} \, \text{m} \)
- Distance between the slits, \( d = 2 \, \text{mm} = 2 \times 10^{-3} \, \text{m} \)
- Distance from the slits to the screen, \( D = 140 \, \text{cm} = 1.4 \, \text{m} \)

### Step 2: Use the formula for the position of the bright fringe
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