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In the above problem if block is release...

In the above problem if block is released from there, what would be maximum extension.

Text Solution

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Let `x_(0) =` maximum extension
applying conservation of energy
`mgx_(0) = (1)/(2) Kx_(0)^(2)`
The velocity at the point of maximum extension is zero.
`x_(0) = (2mg)/(K)` is maximum extension, Ans. `(mg)/(K)`
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