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A wave travels on a light string. The eq...

A wave travels on a light string. The equation of the waves is `y= A sin (kx - omegat + 30^@)`. It is reflected from a heavy string tied to an end of the light string at x = 0. If 64% of the incident energy is reflected, then the equation of the reflected wave is

A

`Y = 0.8 A sin (kx - omegat + 30^(@) + 180^(@))`

B

`Y = 0.8 A sin (kx + omegat + 30^(@) + 180^(@))`

C

`Y = 0.8 A sin (kx + omegat - 30^(@))`

D

`Y = 0.8 A sin (kx + omegat + 30^(@))`

Text Solution

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The correct Answer is:
C
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