A pulse is started at a time `t = 0` along the `+x` directions an a long, taut string. The shaot of the puise at `t = 0` is given by funcation `y` with
`y = {{:((x)/(4)+1fo r-4ltxle0),(-x+1fo r0ltxlt1),("0 otherwise"):}`
here `y` and `x` are in centimeters. The linear mass density of the string is `50 g//m` and it is under a tension of `5N`,
the shape of the string is drawn at `t = 0` and lthe area of the pulse elclosed by the string and the `x-`string is measured. It will be equal to `

Options

A. `2 cm^(2)`
B. `2.5 cm^(2)`
C. `4 cm^(2)`
D. `5 cm^(2)`

Answer

B

Explanation

Shape of the pulse at `t = 0`
That is a triangular pulse Area of the pulse
`= (1)/(2)[(4 xx 1) + (1 xx 1)]`
`= (5)/(2) cm^(2)`