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Hydrogen bonding does not play role in t...

Hydrogen bonding does not play role in the boiling point of :

A

`NH_(3)`

B

`H_(2)O`

C

`HI`

D

`HF`

Text Solution

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The correct Answer is:
To determine which compound does not exhibit hydrogen bonding and therefore does not have its boiling point influenced by it, we can follow these steps: ### Step-by-Step Solution: 1. **Understand Hydrogen Bonding**: - Hydrogen bonding occurs when hydrogen is covalently bonded to highly electronegative elements such as fluorine (F), oxygen (O), or nitrogen (N). 2. **Analyze Each Option**: - **Option A: NH3 (Ammonia)** - Ammonia has hydrogen bonded to nitrogen. Since nitrogen is one of the elements that can participate in hydrogen bonding, NH3 does exhibit hydrogen bonding. - **Option B: H2O (Water)** - Water has hydrogen bonded to oxygen. Oxygen is also part of the FON group, so H2O exhibits hydrogen bonding. - **Option C: HF (Hydrogen Fluoride)** - Hydrogen fluoride has hydrogen bonded to fluorine. Fluorine is the most electronegative element, and HF exhibits strong hydrogen bonding. - **Option D: HI (Hydrogen Iodide)** - Hydrogen iodide has hydrogen bonded to iodine. Iodine is not as electronegative as nitrogen, oxygen, or fluorine, and thus HI does not exhibit hydrogen bonding. 3. **Conclusion**: - Since HI does not participate in hydrogen bonding, it does not have its boiling point influenced by hydrogen bonding. Therefore, the answer to the question is HI. ### Final Answer: The compound in which hydrogen bonding does not play a role in the boiling point is **HI (option C)**. ---
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