The formation of `O_(2)^(+)[PtF_(6)]^(-)` is the basis for the formation of xenon fluorides. This is because:

Options

A. `O_(2)` and `Xe` have comparable sizes.
B. both `O_(2)` and Xe are gases.
C. `O_(2)` and Xe have comparable ionisation energies.
D. `O_(2)` and Xe have comparable electronegativities.

Answer

To understand why the formation of `O2^(+) [PtF6]^(-)` is the basis for the formation of xenon fluorides, we can break down the reasoning into a step-by-step solution.

### Step-by-Step Solution:

1. **Understanding Ionization Energies**:
- The ionization energy is the energy required to remove an electron from an atom or ion. In this case, we are comparing the ionization energies of oxygen and xenon.
- The ionization energy of oxygen is approximately 1175 kJ/mol, while that of xenon is around 1170 kJ/mol.

2. **Comparing Ionization Energies**:
- The closeness of the ionization energies (1175 kJ/mol for O and 1170 kJ/mol for Xe) indicates that both elements can exhibit similar chemical behavior when it comes to forming positive ions.
- This similarity suggests that xenon can participate in reactions in a manner analogous to oxygen.

3. **Formation of `O2^(+) [PtF6]^(-)`**:
- Neil Bartlett discovered that when oxygen gas (`O2`) reacts with platinum hexafluoride (`PtF6`), it forms the complex ion `O2^(+) [PtF6]^(-)`.
- This reaction demonstrates that `O2` can lose an electron to form a positively charged ion, which is stabilized by the `PtF6` complex.

4. **Application to Xenon**:
- Given the similar ionization energies, Bartlett hypothesized that xenon could also react with `PtF6` in a similar manner.
- Thus, when xenon is introduced to `PtF6`, it can also form a complex, leading to the discovery of xenon fluorides.

5. **Conclusion**:
- The key reason for the formation of xenon fluorides from the reaction of `O2` and `PtF6` is the comparable ionization enthalpies of oxygen and xenon. This similarity allows xenon to behave like oxygen in forming complexes with fluorine.

### Final Answer:
The formation of `O2^(+) [PtF6]^(-)` is the basis for the formation of xenon fluorides because the ionization enthalpies of oxygen and xenon are comparable, allowing xenon to participate in similar reactions.

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