Statement-1 : Hydrolysis of `XeF_(6)` represents a redox reaction.
Statement-2 : The products of hydrolysis are `XeOF_(4)` and `XeO_(3)` where the oxidation states of all elements remain the same as it was in the reacting state.

Options

A. Statement-1 is True, Statement-2 is True,Statement-2 is a correct explanation for Statement-1.
B. Statement-1 is True, Statement-2 is True,Statement-2 is NOT a correct explalanation for Statement-7
C. Statement-1 is True, Statement-2 is False
D. Statement-1 is False, Statement-2 is True

Answer

To analyze the statements regarding the hydrolysis of \( \text{XeF}_6 \), we will break down the problem step by step.

### Step 1: Write the hydrolysis reaction of \( \text{XeF}_6 \)

The hydrolysis of \( \text{XeF}_6 \) can be represented as:
\[ \text{XeF}_6 + \text{H}_2\text{O} \rightarrow \text{XeOF}_4 + \text{XeO}_3 + \text{HF} \]
This reaction shows that \( \text{XeF}_6 \) reacts with water to produce several products.

### Step 2: Determine the oxidation states of xenon in reactants and products

1. In \( \text{XeF}_6 \):
- The oxidation state of xenon (Xe) is +6. This is calculated as follows:
\[ \text{Oxidation state of Xe} + 6 \times (-1) = 0 \implies \text{Oxidation state of Xe} = +6 \]

2. In \( \text{XeOF}_4 \):
- The oxidation state of xenon is also +6. This can be calculated as:
\[ \text{Oxidation state of Xe} + (-2) + 4 \times (-1) = 0 \implies \text{Oxidation state of Xe} = +6 \]

3. In \( \text{XeO}_3 \):
- The oxidation state of xenon is again +6. This can be calculated as:
\[ \text{Oxidation state of Xe} + 3 \times (-2) = 0 \implies \text{Oxidation state of Xe} = +6 \]

### Step 3: Analyze the oxidation states

From the calculations:
- The oxidation state of xenon in \( \text{XeF}_6 \) is +6.
- The oxidation states of xenon in both \( \text{XeOF}_4 \) and \( \text{XeO}_3 \) are also +6.

### Step 4: Conclusion on redox reaction

Since the oxidation state of xenon does not change during the reaction (it remains +6 throughout), we conclude that there is no oxidation or reduction occurring. Therefore, the hydrolysis of \( \text{XeF}_6 \) does not represent a redox reaction.

### Final Evaluation of Statements

- **Statement 1**: False (the hydrolysis does not represent a redox reaction).
- **Statement 2**: True (the oxidation states of all elements remain the same as in the reacting state).

### Final Answer

Thus, the correct answer is:
- Statement 1 is false.
- Statement 2 is true.