How does `XeO_(3)` reacts with aqueous alkali ?

Answer

To understand how xenon trioxide (XeO₃) reacts with aqueous alkali (such as NaOH), we can break down the reaction step by step.

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in this reaction are xenon trioxide (XeO₃) and sodium hydroxide (NaOH), which is the aqueous alkali.

2. **Write the Chemical Reaction**:
- When xenon trioxide reacts with sodium hydroxide, the reaction can be represented as:
\[ \text{XeO}_3 + \text{NaOH} \rightarrow \text{Na}^+ + \text{H}[\text{XeO}_4]^- \]
- Here, XeO₃ acts as an acid and donates a proton (H⁺) to the hydroxide ion (OH⁻) from NaOH.

3. **Formation of Products**:
- The products formed from this reaction are sodium exonate (NaXeO₄) and water. The complete balanced reaction can be expressed as:
\[ \text{XeO}_3 + \text{NaOH} \rightarrow \text{NaXeO}_4 + \text{H}_2\text{O} \]

4. **Conclusion**:
- Therefore, the reaction of xenon trioxide with aqueous alkali results in the formation of sodium exonate (NaXeO₄) and water.

### Final Answer:
When xenon trioxide (XeO₃) reacts with aqueous alkali (NaOH), it forms sodium exonate (NaXeO₄) and water.

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