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What prompted Bartlett to the discovery of noble gases compounds ?

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### Step-by-Step Solution: 1. **Background on Noble Gases**: Noble gases are known for their lack of reactivity due to their complete valence electron shells. Traditionally, they were thought to be inert and incapable of forming compounds. 2. **Neil Bartlett's Experiment**: Neil Bartlett was a chemist who, in 1962, conducted an experiment involving the oxidation of oxygen in the presence of a compound called PTF6 (platinum hexafluoride). During this experiment, he prepared a red-colored compound. 3. **Ionization Energy Comparison**: Bartlett noticed that the ionization energy of oxygen (1175 kJ/mol) was very similar to that of xenon (1170 kJ/mol). This similarity in ionization energies suggested that if oxygen could form compounds, then perhaps xenon could as well. 4. **Attempt to Create Noble Gas Compounds**: Encouraged by this observation, Bartlett attempted to synthesize a compound involving xenon. He reacted xenon with PTF6, resulting in the formation of xenon hexafluoroplatinate (XePTF6) and other related compounds. 5. **Further Discoveries**: Following his initial success, Bartlett went on to prepare various other compounds of xenon, including oxides and fluorides, which opened the door to the study of noble gas chemistry. ### Conclusion: Bartlett's discovery of noble gas compounds was prompted by his experimental findings with oxygen and PTF6, combined with the realization of the similarity in ionization energies between oxygen and xenon. ---
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RESONANCE ENGLISH-P BLOCK ELEMENTS-Exercise 3 part-3
  1. Give reasons : (i)Xenon does not form fluorides such as XeF(3) and XeF...

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  2. Bleaching of flowers by chlorine is permanet, while that by sulphur di...

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  3. What prompted Bartlett to the discovery of noble gases compounds ?

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  4. Complete the following reactions equations : (i)CaO CI(2)+HCl to (...

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  5. Noble gases are inert to chemical reactivity. This is due to

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  6. Bond dissociation energy of F(2) is less that of Cl(2) give reason.

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  7. What happen when Cl(2) is passed through a hot concentrated solution o...

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  8. How would you account for the following ? (i)The lower oxidation sta...

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  9. Write chemical equations for the following processes : (i) Chlorin...

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  10. Explain why the electrons gain enthalpy of fluorine is less negative t...

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  11. Draw the structures of the following molecules : (i) XeF(4) (ii) B...

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  12. F(2) is a stronger oxidising agent than Cl(2)

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  13. The majority of noble gas compounds are those of xenon. Explain.

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  14. No chemical compound of helium is known.

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  15. XeF(2) has linear structure and not a bent structure , Given reason .

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  16. Why fluorine never acts as the central atom in polyatomic interhalogen...

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  17. (a) (i) Complete the following chemical equations : (i)NaOH((aq))+...

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  18. Why fluorine does not exhibit any positive oxidation state?

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  19. Explain the following : (a) The electron gain enthalpy with negative...

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  20. Draw the structure of XeF(2)

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