Fluorine is obtained by the interaction of `K_2MnF_6` with Lewis acid `SbF_5` because of the :

Options

A. Acidolysis of `MnF_4`
B. Decomposition of `MnF_4`
C. Ionization of `MnF_4`
D. Decomposition of `SbF_6`

Answer

To solve the question of why fluorine is obtained by the interaction of \( K_2MnF_6 \) with the Lewis acid \( SbF_5 \), we can break down the process step by step:

### Step 1: Understanding the Reactants
- We start with \( K_2MnF_6 \) (Potassium Manganese Hexafluoride) and \( SbF_5 \) (Antimony Pentafluoride).
- \( SbF_5 \) is a strong Lewis acid, which means it can accept electron pairs.

**Hint:** Identify the nature of the reactants and their roles in the reaction.

### Step 2: Reaction Between \( K_2MnF_6 \) and \( SbF_5 \)
- When \( K_2MnF_6 \) reacts with \( SbF_5 \), it forms \( KSBF_6 \) (Potassium Antimony Fluoride) and \( MnF_4 \) (Manganese Tetrafluoride).
- The balanced reaction can be written as:
\[ 2K_2MnF_6 + 4SbF_5 \rightarrow 4KSBF_6 + 2MnF_4 \]

**Hint:** Write down the balanced chemical equation for the initial reaction.

### Step 3: Decomposition of \( MnF_4 \)
- \( MnF_4 \) is unstable and can decompose further.
- The decomposition of \( MnF_4 \) produces \( MnF_3 \) (Manganese Trifluoride) and \( F_2 \) (Fluorine gas):
\[ 2MnF_4 \rightarrow 2MnF_3 + F_2 \]

**Hint:** Consider the stability of the products formed and how they can further react.

### Step 4: Overall Reaction
- Combining the two reactions, we get the overall process:
\[ 2K_2MnF_6 + 4SbF_5 \rightarrow 4KSBF_6 + 2MnF_3 + F_2 \]
- This shows that fluorine gas \( F_2 \) is liberated as a product.

**Hint:** Summarize the overall reaction to see how \( F_2 \) is produced.

### Conclusion
- The reason fluorine is obtained from the interaction of \( K_2MnF_6 \) with \( SbF_5 \) is due to the decomposition of \( MnF_4 \) which is formed in the reaction. The unstable \( MnF_4 \) decomposes to yield \( F_2 \).

**Final Answer:** Fluorine is obtained by the interaction of \( K_2MnF_6 \) with \( SbF_5 \) because of the decomposition of \( MnF_4 \).