The reaction of `KMnO_(4) and HCI` results in:

Answer

To determine the products of the reaction between potassium permanganate (KMnO4) and hydrochloric acid (HCl), we can follow these steps:

### Step 1: Write the Reactants
The reactants in this reaction are potassium permanganate (KMnO4) and hydrochloric acid (HCl).

### Step 2: Identify the Products
When KMnO4 reacts with HCl, the products formed are potassium chloride (KCl), manganese(II) chloride (MnCl2), water (H2O), and chlorine gas (Cl2).

### Step 3: Write the Unbalanced Equation
The unbalanced chemical equation for the reaction can be written as:
\[ KMnO_4 + HCl \rightarrow KCl + MnCl_2 + H_2O + Cl_2 \]

### Step 4: Balance the Equation
To balance the equation, we need to ensure that the number of atoms for each element is the same on both sides. The balanced equation is:
\[ 2 KMnO_4 + 16 HCl \rightarrow 2 KCl + 2 MnCl_2 + 8 H_2O + 8 Cl_2 \]

### Step 5: Determine Oxidation States
In KMnO4, manganese (Mn) has an oxidation state of +7. In MnCl2, manganese has an oxidation state of +2. Therefore, manganese is reduced from +7 to +2.

### Step 6: Identify the Changes in Oxidation States
Chlorine in HCl has an oxidation state of -1, and in Cl2 (chlorine gas), it has an oxidation state of 0. Thus, chlorine is oxidized from -1 to 0.

### Conclusion
The overall reaction shows that manganese is reduced while chlorine is oxidized. The final products of the reaction are potassium chloride (KCl), manganese(II) chloride (MnCl2), water (H2O), and chlorine gas (Cl2).

### Final Balanced Reaction
\[ 2 KMnO_4 + 16 HCl \rightarrow 2 KCl + 2 MnCl_2 + 8 H_2O + 8 Cl_2 \]