A certain compound (X) shows the following reactions.
(i)When Kl is added to an aqueous suspension of (X) containing dilute HCl, iodine is liberated.
(ii)When the paste of (X) in water is heated with acetone, a product of anesthetic use is obtained.
(iii)When `CO_(2)` is passed through an aqueous suspension of (X) the turbidity transforms to a precipitate.
Identify (X) and write down chemical equations for the step (i),(ii) & (iii)

Answer

To identify the compound (X) and write down the chemical equations for the given reactions, we can analyze each reaction step by step.

### Step 1: Identify the compound (X)

From the first reaction, we can deduce that the compound (X) is Calcium Oxychloride, represented as \( \text{Ca(OCl)}_2 \) or \( \text{CaOCl}_2 \).

### Step 2: Reaction (i)

**Reaction Description**: When KI is added to an aqueous suspension of (X) containing dilute HCl, iodine is liberated.

**Chemical Equation**:
1. \( \text{Ca(OCl)}_2 + 2 \text{HCl} \rightarrow \text{CaCl}_2 + \text{Cl}_2 + \text{H}_2\text{O} \)
2. \( \text{Cl}_2 + 2 \text{KI} \rightarrow 2 \text{KCl} + \text{I}_2 \)

**Overall Reaction**:
\[ \text{Ca(OCl)}_2 + 2 \text{HCl} + 2 \text{KI} \rightarrow \text{CaCl}_2 + 2 \text{KCl} + \text{I}_2 + \text{H}_2\text{O} \]

### Step 3: Reaction (ii)

**Reaction Description**: When the paste of (X) in water is heated with acetone, a product of anesthetic use is obtained.

**Chemical Equation**:
1. \( \text{Ca(OCl)}_2 + 2 \text{H}_2\text{O} \rightarrow \text{Ca(OH)}_2 + \text{Cl}_2 \)
2. \( \text{Cl}_2 + \text{CH}_3\text{COCH}_3 \rightarrow \text{CCl}_3\text{COCH}_3 + 3 \text{HCl} \)
3. \( \text{CCl}_3\text{COCH}_3 + \text{Ca(OH)}_2 \rightarrow \text{CHCl}_3 + \text{CaCO}_3 + \text{H}_2\text{O} \)

**Overall Reaction**:
\[ \text{Ca(OCl)}_2 + 2 \text{CH}_3\text{COCH}_3 + 2 \text{H}_2\text{O} \rightarrow \text{CHCl}_3 + \text{CaCO}_3 + 3 \text{HCl} \]

### Step 4: Reaction (iii)

**Reaction Description**: When \( \text{CO}_2 \) is passed through an aqueous suspension of (X), the turbidity transforms to a precipitate.

**Chemical Equation**:
1. \( \text{Ca(OCl)}_2 + \text{CO}_2 + \text{H}_2\text{O} \rightarrow \text{CaCO}_3 + \text{Cl}_2 \)

**Overall Reaction**:
\[ \text{Ca(OCl)}_2 + \text{CO}_2 + \text{H}_2\text{O} \rightarrow \text{CaCO}_3 \downarrow + \text{Cl}_2 \]

### Conclusion

The compound (X) is \( \text{Ca(OCl)}_2 \) (Calcium Oxychloride). The reactions can be summarized as follows:

1. \( \text{Ca(OCl)}_2 + 2 \text{HCl} + 2 \text{KI} \rightarrow \text{CaCl}_2 + 2 \text{KCl} + \text{I}_2 + \text{H}_2\text{O} \)
2. \( \text{Ca(OCl)}_2 + 2 \text{CH}_3\text{COCH}_3 + 2 \text{H}_2\text{O} \rightarrow \text{CHCl}_3 + \text{CaCO}_3 + 3 \text{HCl} \)
3. \( \text{Ca(OCl)}_2 + \text{CO}_2 + \text{H}_2\text{O} \rightarrow \text{CaCO}_3 \downarrow + \text{Cl}_2 \)