Distillation of HBr and `HBrO_3` yields bromine gas.

Answer

To determine whether the statement "Distillation of HBr and HBrO3 yields bromine gas" is true, we need to analyze the reaction between hydrobromic acid (HBr) and bromic acid (HBrO3).

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants in this case are hydrobromic acid (HBr) and bromic acid (HBrO3).

2. **Write the Reaction**:
When HBr reacts with HBrO3, the products formed are water (H2O) and bromine gas (Br2). The reaction can be written as:
\[ \text{HBr} + \text{HBrO}_3 \rightarrow \text{Br}_2 + \text{H}_2\text{O} \]

3. **Balance the Reaction**:
To ensure that the equation is balanced, we need to count the number of atoms of each element on both sides of the equation.
- On the left side:
- H: 2 (1 from HBr and 1 from HBrO3)
- Br: 2 (1 from HBr and 1 from HBrO3)
- O: 3 (from HBrO3)
- On the right side:
- H: 2 (from H2O)
- Br: 2 (from Br2)
- O: 1 (from H2O)

To balance the oxygen, we need to ensure that we have the same number of oxygen atoms on both sides. The balanced equation is:
\[ 3 \text{HBr} + \text{HBrO}_3 \rightarrow \text{Br}_2 + 3 \text{H}_2\text{O} \]

4. **Conclusion**:
Since the balanced equation shows that bromine gas (Br2) is indeed produced as a product of the reaction between HBr and HBrO3, the statement "Distillation of HBr and HBrO3 yields bromine gas" is true.

### Final Answer:
The statement is true; the distillation of HBr and HBrO3 yields bromine gas.