`Pl_3` on hydrolysis yields `H_3PO_3` and HI

Answer

To determine whether the statement "Phosphorus triiodide (P₃I) on hydrolysis yields H₃PO₃ and HI" is true or false, we can analyze the hydrolysis reaction step by step.

### Step 1: Write the reaction for hydrolysis of phosphorus triiodide
Phosphorus triiodide (P₃I) reacts with water (H₂O) during hydrolysis. The general reaction can be expressed as:
\[ \text{P}_3\text{I} + \text{H}_2\text{O} \rightarrow \text{H}_3\text{PO}_3 + \text{HI} \]

### Step 2: Identify the products
From the hydrolysis of phosphorus triiodide, we need to identify the products. The expected products are:
- H₃PO₃ (phosphorous acid)
- HI (hydrogen iodide)

### Step 3: Check the balance of the reaction
Next, we need to ensure that the reaction is balanced. The balanced equation should have the same number of each type of atom on both sides.

1. **Count the iodine atoms**:
- Left side: 3 I (from P₃I)
- Right side: 1 I (from HI) → We need 3 HI to balance the iodine.

2. **Count the hydrogen atoms**:
- Left side: 2 H (from H₂O)
- Right side: 3 H (from H₃PO₃) + 3 H (from 3 HI) = 6 H → We need 4 H₂O to balance the hydrogen.

3. **Count the phosphorus and oxygen atoms**:
- Phosphorus: 3 P (from P₃I) and 1 P (from H₃PO₃) → This is balanced as we have 3 phosphorus atoms.
- Oxygen: 4 O (from 4 H₂O) and 3 O (from H₃PO₃) → This is balanced as we have 4 oxygen atoms.

### Step 4: Write the balanced equation
The balanced equation for the reaction is:
\[ \text{P}_3\text{I} + 4 \text{H}_2\text{O} \rightarrow \text{H}_3\text{PO}_3 + 3 \text{HI} \]

### Conclusion
Since the reaction is balanced and the products are correctly identified as H₃PO₃ and HI, we can conclude that the statement is **true**.