Cesium fluoride reacts with `XeF_(6)` to form ________

Answer

To solve the question regarding the reaction between cesium fluoride (CsF) and xenon hexafluoride (XeF6), we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are cesium fluoride (CsF) and xenon hexafluoride (XeF6).

### Step 2: Understand the Nature of the Reactants
Cesium fluoride is an ionic compound where cesium (Cs) has a +1 oxidation state and fluoride (F) has a -1 oxidation state. Xenon hexafluoride is a covalent compound where xenon (Xe) is in a +6 oxidation state.

### Step 3: Determine the Product
When cesium fluoride reacts with xenon hexafluoride, it forms a complex. The expected product of this reaction is cesium heptafluoride xenon (CsXeF7). This complex is formed due to the interaction between the cesium cation and the xenon hexafluoride.

### Step 4: Analyze the Structure of the Product
The structure of XeF6 is distorted octahedral, which means that the arrangement of the fluorine atoms around the xenon atom is not perfectly symmetrical due to the presence of lone pairs on the xenon. In the case of CsXeF7, cesium donates its fluoride ion to the xenon, resulting in the formation of the complex.

### Final Answer
Cesium fluoride reacts with xenon hexafluoride to form **CsXeF7**.

---