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At 273 K temperature and 9 atm pressure,...

At 273 K temperature and 9 atm pressure, the compressibility for a gas is 0.9. The volulme of 1 milli-mole of gas at this temperature and pressure is :

A

`2.24 litre`

B

`0.020 mL`

C

`2.24 mL`

D

`22.4 mL`

Text Solution

Verified by Experts

The correct Answer is:
C
`Z = (PV)/(nRT), V = (0.9 xx 0.0821 xx 273)/(9) = 2.24 litre// mol`
`:.` Volume of 1 mili-mole of gas `= 2.24 mL`
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