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What is the compressibility factor (Z) f...

What is the compressibility factor (Z) for 0.02 mole of a van der Waals's gas at pressure of 0.1 atm. Assume the size of gas molecules is negligible.
Given : RT=20 L atm `mol^(-1)` and a=1000 atm `L^(2) mol^(-2)`

A

`2`

B

`1`

C

`0.02`

D

`0.01`

Text Solution

Verified by Experts

The correct Answer is:
D
`(0.1 +(1000xx(0.02)^(2))/(V^(2))) V = 20 xx 0.02 = 0.1 V^(2) - 0.4 V + 0.4 = 0`
`V^(2) - 4V +4 = 0`
`rArr V = 2L`
`Z = (PV)/(RT) = (0.1 xx 2)/(20) = 0.01`
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