The threshold frequency `v_(0)` for a metal is `6xx10^(14) s^(-1)`. Calculate the kinetic energy of an electron emitted when radiation of frequency `v=1.1xx10^(15) s^(-1)` hits the metal.

Explanation

To solve the problem, we will use the photoelectric effect equation, which relates the kinetic energy of emitted electrons to the frequency of the incident radiation and the threshold frequency of the metal.

### Step-by-Step Solution:

1. **Identify Given Values**:
- Threshold frequency, \( v_0 = 6 \times 10^{14} \, \text{s}^{-1} \)
- Frequency of incident radiation, \( v = 1.1 \times 10^{15} \, \text{s}^{-1} \)
- Planck's constant, \( h = 6.626 \times 10^{-34} \, \text{Js} \)
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