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Na^(23) is more stable isotope of Na. Fi...

`Na^(23)` is more stable isotope of `Na`. Find out the process by which `._(11)Na^(24)` can undergo radioactive decay.

Text Solution

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`n//p` ratio of `^(24)Na` is `13//11` and thus greater than one. It will therefore decay following `beta`-emission.
`_(11)^(24)Na rarr `_(12)^(24)Mg+ `_(-1)^(0)e```
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