Consider the following radioactive change `_(11)^(22)Na rarr `_(10)^(22)Ne`
What is the type of particle captured or emitted?

Answer

To solve the problem, we need to analyze the radioactive change given:

\[ _{11}^{22}\text{Na} \rightarrow _{10}^{22}\text{Ne} \]

### Step 1: Identify the initial and final elements
- The initial element is Sodium-22 (Na) with an atomic number of 11.
- The final element is Neon-22 (Ne) with an atomic number of 10.

### Step 2: Determine the change in atomic number
- The atomic number decreases from 11 (Na) to 10 (Ne). This indicates that a particle must have been emitted or captured that reduces the atomic number by 1.

### Step 3: Identify the type of particle involved
- Since the atomic number decreases by 1, this suggests that a **positron** is emitted. Positrons are positively charged particles that can be emitted during certain types of radioactive decay, specifically beta plus decay.

### Step 4: Determine if any particle is captured
- The process can also involve the capture of an electron (this is known as electron capture). In this case, the sodium atom captures an electron, which results in the transformation to neon, decreasing the atomic number by 1.

### Conclusion
- The type of particle captured is an **electron**.
- The type of particle emitted is a **positron**.

### Final Answer
- Captured Particle: Electron
- Emitted Particle: Positron

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